select from one table where count=1 in second table and two more conditions

I need to select transactions with cash payment and same date but only for those transactions
which have only one payment ( so num 14 should be omitted from resultset )
So correct result is 12 and 13 only.

    Table2                          Table1
 num  | date | data | total       num | payment | date
 12      xy     abc    2.5        12      cash     xy
 13      xy     cbc    2.1        13      cash     xy
 14      xy     acc    2.3        14      visa     xy
 19      xy     def    2.0        14      cash     xy
 27      xy     fgh    1.3        19      visa     xy
                                  27       mc      xy  
 

Something like this gives num 14 in result-set but 14 should be omitted.

SELECT num, data 
 FROM Table2
 WHERE num IN
 (
 SELECT num  FROM `Table1`
 WHERE payment = 'cash'
 GROUP BY `num`
 HAVING ( COUNT(`num`) = 1  )
 )        
 

To sumarize correct answer (by tombom ):

 SELECT t2.num, t2.data 
  FROM Table1 as t1
  INNER JOIN Table2 as t2 ON t1.num = t2.num
  AND t1.date = 'xy'  
  GROUP BY t1.num
  HAVING GROUP_CONCAT(t1.payment) = 'cash'
 

Thanks!

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